Odds Of 10 Black In A Row Roulette

  
Odds Of 10 Black In A Row Roulette 4,9/5 2121 votes
evilzebra

Perhaps the most famous example of the gambler's fallacy occurred in a game of roulette at the Monte Carlo Casino on August 18, 1913, when the ball fell in black 26 times in a row. This was an extremely uncommon occurrence: the probability of a sequence of either red or black occurring 26 times in a row is ( 18 / 37 ) 26-1 or around 1 in 66.6. Odds Of 10 Black In A Row Roulette, betway casino script, alladin hotel and casino, rules of 5 card trick in blackjack. Wager All Software.

Let's say you are a strict martingaler. For simplicity sake, you have $1024 to bet with. Here's how your progression would go
Bet Level
1 1
2 2
4 3
8 4
16 5
32 6
64 7
128 8
256 9
512 10
This means that you can afford to lose your bet 9 times in a row, but not 10 times. Assuming you pick a color (red), what is the probability you will get wiped out here. If you lose on the 10th bet, you only have $1 left.
Well, there are 20 colors that aren't red in the roulette wheel.
So that means that the probability of losing a bet is (20/38) which equals 52.6%
Now, the probability of losing 10 bets in a row is probably (20/38) ^ 10
I get .00163
That means that out of 10000 spins, only 16 times will a streak of 10 or more occur.
Is this math right, or am I missing something?
rottenluck
Your math is right. 16 wipe outs per 1,000 attempts.
GWAE
Where can you play at $1 min
Expect the worst and you will never be disappointed. I AM NOT PART OF GWAE RADIO SHOW
evilzebra

Your math is right. 16 wipe outs per 1,000 attempts.


I think you're off by a magnitude of 10. It should be 16/10,000
DJTeddyBear
Yeah, your math is right, but ... What's the point?
I mean, let's say you lose 3 times then win, or 7 times then win, or all 9 times then win. When you win and add up all your money, you're up one whole dollar.
Are you really prepared to risk $1,024 to win one buck?
Well, even if you said yes, the casino isn't prepared to let you try. Casinos typically do not have that much of a range between the minimum and maximum bet.
Additionally, you're gonna have to multiply your bankroll by 5 (or maybe 10) as typical casino minimums are $5 (or $10).
I invented a few casino games. Info: http://www.DaveMillerGaming.com/ ————————————————————————————————————— Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁
OnceDear
Administrator


That means that out of 10000 spins, only 16 times will a streak of 10 or more occur.
Is this math right, or am I missing something?


Each of those 16 times you will lose $1023, which is $16368 lost
If you won ALL the other 9840 wagers, that would give you $9840 of winnings to offset against those losses. But that would be pretty miraculous.

Odds Of 10 Black In A Row Roulette Numbers


You'd maybe win about half (18/38) or 4661 of wagers giving you a more realistic $4661 of winnings to offset against your losses.
Academic really as on wipeout number one you are wiped out.
Marty is good for when you have £1000 and NEED $1001 to escape a firing squad or fly out of a war zone. Other than that it's just a fun way to lose your money.
Take care out there. Spare a thought for the newly poor who were happy in their world just a few days ago, but whose whole way of life just collapsed..
RS
Odds Of 10 Black In A Row Roulette
18 red, 18 black, 2 green.
20 losers, 18 winners. 38 total.
(20/38) ^ 10 = 0.00163103767 ~ 0.00164 = 0.164% [rounded to 0.164% to give martingaler benefit of the doubt].
For ease of use, let's say you decide to play 100,000 cycles (a cycle is when you first bet $1, until you win or lose 10 in a row...a cycle is NOT 100,000 wagers).
For 100K cycles, you expect to lose 164 of those. The remaining 99,846 cycles, you will win $1. For the 164 losing cycles, you will lose $1,023.
164 * 1,023 = $167,772.
99,846 * 1 = $99,846.
$167,772 - $99,846 = -$67,926.
OnceDear
Administrator


164 * 1,023 = $167,772.
99,846 * 1 = $99,846.
$167,772 - $99,846 = -$67,926.


Maybe More accurate. Equally devastatingly bad.
Actually, RS, 100,000 cycles would be way more than 100,000 wagers, More like 200,000. so wouldn't likely number of lost cycles be about double too.. Cannot be bothered to do the proper maths right now. Hmmmmm. will give more thought to RS's cycles approach to see if reality is dumb to the tune of 67K or something maybe half or so of that.
Marty is still SSssoooooo dumb if there is a house edge, and as to double Zero Roulette. PaH!!!
Take care out there. Spare a thought for the newly poor who were happy in their world just a few days ago, but whose whole way of life just collapsed..

With the exception of a tiny handful of punters, no player can beat the tables consistently without taking advantage of great streaks of luck. Beating roulette with streak bets can be both fun and profitable.

Roulette players tend to love their game so much that they adhere to what Nick “The Greek” Dandalos said, “The only thing as good as gambling and winning, is gambling and losing.”

In an effort to find any way possible to supplement or enhance their chances at the roulette table, enthusiasts tend to use betting systems that increase their time at the table without necessarily increasing their overall odds of winning.

The simple fact of roulette is that the house has the advantage and will win one more bet out of every 37 spins than the player. However, roulette betting systems can take advantage of streaks and provide a player with the opportunity to increase their bankrolls in specific situations.

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10
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2
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9.6
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Numbers

Betting Against a Streak

The Martingale system is one of the best known and easiest to apply betting systems. The player simply doubles their bet each time they lose and waits for a winner. Many roulette players employ this system with an even money bet (odd or even, red or black, first 18 or second 18) after seeing the opposite side hit three times in a row.

The logic that the other side is now due to hit isn’t actually logic at all, it’s the classic gambler’s fallacy that the odds of an event happening are going to even-out quickly by returning a series of events that are the opposite of what has just been observed.

On each spin of the ball, the chance of red coming up is 48.7%. On a single zero wheel, if a bet on red wins .487% of the time, the odds of two consecutive red spins is .237, three in a row is .115, four in a row is .0562, and five in a row is .0274. That means a streak of five happens about once in 36.5 spins, and we’ll round up to 37.

So, if you see four straight black spins, does that mean the next spin has to be red (or green) except in one case out of 37? No. The odds are still 48.7% that black is coming back. However, that’s what keeps Martingale players using their system. They will win their small bet many times before they run into a streak that wipes out their current table bankroll.

A player will see six consecutive black spins about once in 75 spins, seven consecutive about once in 154 spins. That’s why Martingale players can win so many times, build up a little bankroll, and have it in their head that the system is a winner. Because of those long odds, a player may win 100, 200, or even 300 straight betting opportunities.

Want to give it a try yourself? Give Lonnie’s roulette simulations a look – click on bet, make the number of spins 100, and see if you get a streak of over 7 on an even-money bet. The results might surprise you!

Games

Dodging the bullet of casino odds is like Russian roulette and you’ve got five chances out of six of winning, and one chance in six that will blow your bankroll out of the water. The problem with the Martingale and many other roulette systems is that you are constantly risking a small fortune to win a single bet. Give it a shot, win a few bets, and consider yourself lucky. Don’t expect it to always work.

Betting With a Streak

Black

Odds Of 10 Black In A Row Roulette Table

Instead of betting against a streak, some players have had great success by anticipating a streak of even-money outcomes continuing. With this system, the player simply chooses an even-money bet (odd/even, red/black, 1-18/19-36) and places a single five-unit wager. When it loses it is replaced with a new five unit wager. When it wins, let the winnings ride until it wins five straight times for a payoff of 155 units.

Odds Of 10 Black In A Row Roulette Games

If every bet was a win or a loss, the house would win its 2.7% and that would be it. However, due to several small streaks happening before a streak of five straight appears, the bettor will not lose 19 of every 37 spins. However, it can be a good stretch before a winning streak of five straight appears.

Odds Of 10 Black In A Row Roulette

An added twist to this strategy is to pull back a single chip after the first three wins of 5, 10, and 20, so 35 rides on the bet. If this wins, two chips are pulled back so 60 rides. If the bet wins again, either the total of 120 is pulled back, or four chips are pulled back and 100 rides. If the 100 bet wins, the entire 200 is now pulled back and the opposite side of the bet (even – now odd, etc.) is made for a single 5-unit wager.

Odds Of 10 Black In A Row Roulette Game

Experiment with your own mixture of these bets to find a happy medium. If you don’t have a wheel at home, try the free online roulette game on the American, European or French roulette pages.

Barring that, you can always take a deck of cards and make your own set-up of 18 even numbers, 18 odd numbers, and an ace to represent the zero, and shuffle away to try a streak system.